Math2.org Math Tables: Integral tanh(x) |
(Math) |
|
|
sinh x
cosh x |
= |
(ex + e-x) / 2 |
tanh x dx = |
ex + e-x |
dx |
set
u = ex + e-x
then we find
du = (ex - e-x) dx
substitute du= (ex - e-x) dx, u = ex
+ e-x
= |
u |
solve
= ln |u| + C
substitute back u = ex + e-x
= ln |ex + e-x| + C
since ex and e-x are always positive
= ln (ex + e-x) + C
since (ex + e-x)/2 = cosh(x)
= ln (2 cosh x) + C
= ln 2 + ln (cosh x) + C
ln 2 is merely a constant that can be combined with C
= ln (cosh x) + C
Q.E.D.