= lim (n->
) ( 1 + 1/2 + 1/3 + 1/4 + ... + 1/n - ln(n) ) = 0.5772156649... = 0.5772156649 0153286061 ...
= lim (n->) ( 1 + 1/2 + 1/3 + 1/4 + ... + 1/n - ln(n) ) = 0.5772156649...
\[\gamma = -\int_0^\infty e^{-x} \ln x \, dx\]
\[ \Gamma ' (1) = -\gamma \] (see Gamma Function)
